Mean median mode, and range
The mean is the average of all numbers or scores.
- Add up all the scores
- Divide this total by the number of scores you added up.
The median is the middle score, once the scores are in order.
- To find the median, scores must be placed in order from the smallest to biggest. Start counting one off each end. Keep going until you have one score left in the middle.
The mode is the most common score, there may be more than one or none at all.
The range is the highest score - the lowest score.
Task 1:
Find the mean, median, mode and range for each list.
- 2, 2, 4, 6, 11 (Range is 9)(Mode is 2)(Median is 4)(Mean is 5)
- 4, 8, 8, 9, 10, 12, 12 (Range is 8)(Modes are 8 and 12)(Median is 9)(Mean is 9)
- 8, 13, 19, 20 (Range is 12)(No mode)(No Median)(Mean is 15)
- 5, 2, 7, 9, 2 (Range is 7)(Mode is 2)(Median is 7)(Mean is 5)
- 9, 6, 8, 12, 3, 8, 10 (Range is 9)(Mode is 8)(Median is 12)(Mean is 8)
- 8, 0, 23, 14, 7, 14 (Range is 23)(Mode is 14)(Median is 23)(Mean is 11)
Task 2:
Martin and Jack both like cricket. During the cricket season they both score many runs, but who is the better batsman? Each batsman had five turns at bat and scored the following runs. Martin said “I’m the better batsman!” Is Martin correct?
Martin: 14, 9, 21, 9, 47
Jack: 22, 13, 7, 36, 22
- Find the mean for both Martin and Jack’s batting scores.
- Find the median for both Martin and Jack’s batting scores.
- Find the mode for both Martin and Jack’s batting scores.
- Find the range for both Martin and Jack’s batting scores.
- Was Jack correct? Using the information you have gathered, who was the better batsman? Explain your answer.
MEAN
Martin: 20
Jack: 20
MEDIAN
Martin: 21
Jack: 7
MODE
Martin: No mode
Jack: 22
RANGE
Martin: 38
Jack: 15
Task 3
There are two groups of 10 students in Room 11. They all sat the same test. Their test results are as listed. Mya, who is in group B, said, “Our group is better we had three students who got a 10 out of 10. Is Mya correct?
This is my maths work about finding the mean, median, mode and range.